Tom, John and Jack bought some macarons. After Tom ate
25 of his macarons, John ate
34 of his macarons and Jack ate 10 macarons, each of them had the same number of macarons left. Tom had 70 less macarons than John at first.
- How many macarons did Tom have at first?
- How many macarons did the 3 of them buy altogether?
|
Tom |
John |
Jack |
Before |
5 u |
4x3 = 12 u |
3 u + 10 |
Change |
- 2 u |
- 3x3 = - 9 u |
- 10 |
After |
3 u |
1x3 = 3 u |
3 u |
(a)
The number of macarons that Tom and John each had in the end is the same. Make the number of macarons that Tom and John each had in the end the same. LCM of 3 and 1 is 3.
Number of macarons that Tom had less than John at first
= 12 u - 5 u
= 7 u
7 u = 70
1 u = 70 ÷ 7 = 10
Number of macarons that Tom had at first
= 5 u
= 5 x 10
= 50
(b)
Total number of macarons that the 3 of them bought
= 5 u + 12 u + 3 u + 10
= 20 u + 10
= 20 x 10 + 10
= 200 + 10
= 210
Answer(s): (a) 50; (b) 210