Liam, Wesley and Sean bought some shortbreads. After Liam ate ²₇ of his shortbreads, Wesley ate ⁴₅ of his shortbreads and Sean ate 3 shortbreads, each of them had the same number of shortbreads left. Liam had 90 less shortbreads than Wesley at first.

1. How many shortbreads did Liam have at first?
2. How many shortbreads did the 3 of them buy altogether? 

	Liam	Wesley	Sean
Before	7 u	5x5 = 25 u	5 u + 3
Change	- 2 u	- 4x5 = - 20 u	- 3
After	5 u	1x5 = 5 u	5 u

(a)
The number of shortbreads that Liam and Wesley each had in the end is the same. Make the number of shortbreads that Liam and Wesley each had in the end the same.  LCM of 5 and 1 is 5.

Number of shortbreads that Liam had less than Wesley at first
= 25 u - 7 u
= 18 u

18 u = 90

1 u = 90 ÷ 18 = 5

Number of shortbreads that Liam had at first
= 7 u
= 7 x 5
= 35 

(b)
Total number of shortbreads that the 3 of them bought
= 7 u + 25 u + 5 u + 3
= 37 u + 3
= 37 x 5 + 3
= 185 + 3
= 188

Answer(s): (a) 35; (b) 188