Luis, Julian and Wesley bought some macarons. After Luis ate ³₇ of his macarons, Julian ate ¹₂ of his macarons and Wesley ate 11 macarons, each of them had the same number of macarons left. Luis had 5 less macarons than Julian at first.

1. How many macarons did Luis have at first?
2. How many macarons did the 3 of them buy altogether? 

	Luis	Julian	Wesley
Before	7 u	2x4 = 8 u	4 u + 11
Change	- 3 u	- 1x4 = - 4 u	- 11
After	4 u	1x4 = 4 u	4 u

(a)
The number of macarons that Luis and Julian each had in the end is the same. Make the number of macarons that Luis and Julian each had in the end the same.  LCM of 4 and 1 is 4.

Number of macarons that Luis had less than Julian at first
= 8 u - 7 u
= 1 u

1 u = 5

1 u = 5 ÷ 1 = 5

Number of macarons that Luis had at first
= 7 u
= 7 x 5
= 35 

(b)
Total number of macarons that the 3 of them bought
= 7 u + 8 u + 4 u + 11
= 19 u + 11
= 19 x 5 + 11
= 95 + 11
= 106

Answer(s): (a) 35; (b) 106