John, Cody and Dylan bought some wafers. After John ate ²₅ of his wafers, Cody ate ⁴₅ of his wafers and Dylan ate 7 wafers, each of them had the same number of wafers left. John had 120 less wafers than Cody at first.

1. How many wafers did John have at first?
2. How many wafers did the 3 of them buy altogether? 

	John	Cody	Dylan
Before	5 u	5x3 = 15 u	3 u + 7
Change	- 2 u	- 4x3 = - 12 u	- 7
After	3 u	1x3 = 3 u	3 u

(a)
The number of wafers that John and Cody each had in the end is the same. Make the number of wafers that John and Cody each had in the end the same.  LCM of 3 and 1 is 3.

Number of wafers that John had less than Cody at first
= 15 u - 5 u
= 10 u

10 u = 120

1 u = 120 ÷ 10 = 12

Number of wafers that John had at first
= 5 u
= 5 x 12
= 60 

(b)
Total number of wafers that the 3 of them bought
= 5 u + 15 u + 3 u + 7
= 23 u + 7
= 23 x 12 + 7
= 276 + 7
= 283

Answer(s): (a) 60; (b) 283