Seth, Vaidev and Jack bought some croissants. After Seth ate ⁴₇ of his croissants, Vaidev ate ⁴₅ of his croissants and Jack ate 11 croissants, each of them had the same number of croissants left. Seth had 88 less croissants than Vaidev at first.

1. How many croissants did Seth have at first?
2. How many croissants did the 3 of them buy altogether? 

	Seth	Vaidev	Jack
Before	7 u	5x3 = 15 u	3 u + 11
Change	- 4 u	- 4x3 = - 12 u	- 11
After	3 u	1x3 = 3 u	3 u

(a)
The number of croissants that Seth and Vaidev each had in the end is the same. Make the number of croissants that Seth and Vaidev each had in the end the same.  LCM of 3 and 1 is 3.

Number of croissants that Seth had less than Vaidev at first
= 15 u - 7 u
= 8 u

8 u = 88

1 u = 88 ÷ 8 = 11

Number of croissants that Seth had at first
= 7 u
= 7 x 11
= 77 

(b)
Total number of croissants that the 3 of them bought
= 7 u + 15 u + 3 u + 11
= 25 u + 11
= 25 x 11 + 11
= 275 + 11
= 286

Answer(s): (a) 77; (b) 286