Fabian, Elijah and Ken bought some biscuits. After Fabian ate ⁵₈ of his biscuits, Elijah ate ³₄ of his biscuits and Ken ate 5 biscuits, each of them had the same number of biscuits left. Fabian had 48 less biscuits than Elijah at first.

1. How many biscuits did Fabian have at first?
2. How many biscuits did the 3 of them buy altogether? 

	Fabian	Elijah	Ken
Before	8 u	4x3 = 12 u	3 u + 5
Change	- 5 u	- 3x3 = - 9 u	- 5
After	3 u	1x3 = 3 u	3 u

(a)
The number of biscuits that Fabian and Elijah each had in the end is the same. Make the number of biscuits that Fabian and Elijah each had in the end the same.  LCM of 3 and 1 is 3.

Number of biscuits that Fabian had less than Elijah at first
= 12 u - 8 u
= 4 u

4 u = 48

1 u = 48 ÷ 4 = 12

Number of biscuits that Fabian had at first
= 8 u
= 8 x 12
= 96 

(b)
Total number of biscuits that the 3 of them bought
= 8 u + 12 u + 3 u + 5
= 23 u + 5
= 23 x 12 + 5
= 276 + 5
= 281

Answer(s): (a) 96; (b) 281