Ahmad, Reggie and Fred bought some wafers. After Ahmad ate ²₅ of his wafers, Reggie ate ²₃ of his wafers and Fred ate 11 wafers, each of them had the same number of wafers left. Ahmad had 8 less wafers than Reggie at first.

1. How many wafers did Ahmad have at first?
2. How many wafers did the 3 of them buy altogether? 

	Ahmad	Reggie	Fred
Before	5 u	3x3 = 9 u	3 u + 11
Change	- 2 u	- 2x3 = - 6 u	- 11
After	3 u	1x3 = 3 u	3 u

(a)
The number of wafers that Ahmad and Reggie each had in the end is the same. Make the number of wafers that Ahmad and Reggie each had in the end the same.  LCM of 3 and 1 is 3.

Number of wafers that Ahmad had less than Reggie at first
= 9 u - 5 u
= 4 u

4 u = 8

1 u = 8 ÷ 4 = 2

Number of wafers that Ahmad had at first
= 5 u
= 5 x 2
= 10 

(b)
Total number of wafers that the 3 of them bought
= 5 u + 9 u + 3 u + 11
= 17 u + 11
= 17 x 2 + 11
= 34 + 11
= 45

Answer(s): (a) 10; (b) 45