Ivan, Charlie and Simon bought some macarons. After Ivan ate ⁴₇ of his macarons, Charlie ate ¹₂ of his macarons and Simon ate 12 macarons, each of them had the same number of macarons left. Ivan had -11 less macarons than Charlie at first.

1. How many macarons did Ivan have at first?
2. How many macarons did the 3 of them buy altogether? 

	Ivan	Charlie	Simon
Before	7 u	2x3 = 6 u	3 u + 12
Change	- 4 u	- 1x3 = - 3 u	- 12
After	3 u	1x3 = 3 u	3 u

(a)
The number of macarons that Ivan and Charlie each had in the end is the same. Make the number of macarons that Ivan and Charlie each had in the end the same.  LCM of 3 and 1 is 3.

Number of macarons that Ivan had less than Charlie at first
= 6 u - 7 u
= -1 u

-1 u = -11

1 u = -11 ÷ -1 = 11

Number of macarons that Ivan had at first
= 7 u
= 7 x 11
= 77 

(b)
Total number of macarons that the 3 of them bought
= 7 u + 6 u + 3 u + 12
= 16 u + 12
= 16 x 11 + 12
= 176 + 12
= 188

Answer(s): (a) 77; (b) 188