Caden, Julian and Ethan bought some wafers. After Caden ate ⁵₈ of his wafers, Julian ate ³₄ of his wafers and Ethan ate 4 wafers, each of them had the same number of wafers left. Caden had 20 less wafers than Julian at first.

1. How many wafers did Caden have at first?
2. How many wafers did the 3 of them buy altogether? 

	Caden	Julian	Ethan
Before	8 u	4x3 = 12 u	3 u + 4
Change	- 5 u	- 3x3 = - 9 u	- 4
After	3 u	1x3 = 3 u	3 u

(a)
The number of wafers that Caden and Julian each had in the end is the same. Make the number of wafers that Caden and Julian each had in the end the same.  LCM of 3 and 1 is 3.

Number of wafers that Caden had less than Julian at first
= 12 u - 8 u
= 4 u

4 u = 20

1 u = 20 ÷ 4 = 5

Number of wafers that Caden had at first
= 8 u
= 8 x 5
= 40 

(b)
Total number of wafers that the 3 of them bought
= 8 u + 12 u + 3 u + 4
= 23 u + 4
= 23 x 5 + 4
= 115 + 4
= 119

Answer(s): (a) 40; (b) 119