Caden, Ahmad and Ivan bought some tarts. After Caden ate
27 of his tarts, Ahmad ate
12 of his tarts and Ivan ate 3 tarts, each of them had the same number of tarts left. Caden had 9 less tarts than Ahmad at first.
- How many tarts did Caden have at first?
- How many tarts did the 3 of them buy altogether?
| |
Caden |
Ahmad |
Ivan |
Before |
7 u |
2x5 =
10 u |
5 u + 3 |
Change |
- 2 u |
- 1x5 =
- 5 u |
- 3 |
After |
5 u |
1x5 =
5 u |
5 u |
(a)
The number of tarts that Caden and Ahmad each had in the end is the same. Make the number of tarts that Caden and Ahmad each had in the end the same. LCM of 5 and 1 is 5.
Number of tarts that Caden had less than Ahmad at first
= 10 u - 7 u
= 3 u
3 u = 9
1 u = 9 ÷ 3 = 3
Number of tarts that Caden had at first
= 7 u
= 7 x 3
= 21
(b)
Total number of tarts that the 3 of them bought
= 7 u + 10 u + 5 u + 3
= 22 u + 3
= 22 x 3 + 3
= 66 + 3
= 69
Answer(s): (a) 21; (b) 69
