Luis, Jack and Xavier bought some puffs. After Luis ate
38 of his puffs, Jack ate
34 of his puffs and Xavier ate 6 puffs, each of them had the same number of puffs left. Luis had 48 less puffs than Jack at first.
- How many puffs did Luis have at first?
- How many puffs did the 3 of them buy altogether?
| |
Luis |
Jack |
Xavier |
Before |
8 u |
4x5 =
20 u |
5 u + 6 |
Change |
- 3 u |
- 3x5 =
- 15 u |
- 6 |
After |
5 u |
1x5 =
5 u |
5 u |
(a)
The number of puffs that Luis and Jack each had in the end is the same. Make the number of puffs that Luis and Jack each had in the end the same. LCM of 5 and 1 is 5.
Number of puffs that Luis had less than Jack at first
= 20 u - 8 u
= 12 u
12 u = 48
1 u = 48 ÷ 12 = 4
Number of puffs that Luis had at first
= 8 u
= 8 x 4
= 32
(b)
Total number of puffs that the 3 of them bought
= 8 u + 20 u + 5 u + 6
= 33 u + 6
= 33 x 4 + 6
= 132 + 6
= 138
Answer(s): (a) 32; (b) 138
