Seth, Jack and Bryan bought some scones. After Seth ate
38 of his scones, Jack ate
12 of his scones and Bryan ate 4 scones, each of them had the same number of scones left. Seth had 6 less scones than Jack at first.
- How many scones did Seth have at first?
- How many scones did the 3 of them buy altogether?
| |
Seth |
Jack |
Bryan |
Before |
8 u |
2x5 =
10 u |
5 u + 4 |
Change |
- 3 u |
- 1x5 =
- 5 u |
- 4 |
After |
5 u |
1x5 =
5 u |
5 u |
(a)
The number of scones that Seth and Jack each had in the end is the same. Make the number of scones that Seth and Jack each had in the end the same. LCM of 5 and 1 is 5.
Number of scones that Seth had less than Jack at first
= 10 u - 8 u
= 2 u
2 u = 6
1 u = 6 ÷ 2 = 3
Number of scones that Seth had at first
= 8 u
= 8 x 3
= 24
(b)
Total number of scones that the 3 of them bought
= 8 u + 10 u + 5 u + 4
= 23 u + 4
= 23 x 3 + 4
= 69 + 4
= 73
Answer(s): (a) 24; (b) 73
