Jenson, Paul and Ahmad bought some cookies. After Jenson ate ²₇ of his cookies, Paul ate ¹₂ of his cookies and Ahmad ate 5 cookies, each of them had the same number of cookies left. Jenson had 18 less cookies than Paul at first.

1. How many cookies did Jenson have at first?
2. How many cookies did the 3 of them buy altogether? 

	Jenson	Paul	Ahmad
Before	7 u	2x5 = 10 u	5 u + 5
Change	- 2 u	- 1x5 = - 5 u	- 5
After	5 u	1x5 = 5 u	5 u

(a)
The number of cookies that Jenson and Paul each had in the end is the same. Make the number of cookies that Jenson and Paul each had in the end the same.  LCM of 5 and 1 is 5.

Number of cookies that Jenson had less than Paul at first
= 10 u - 7 u
= 3 u

3 u = 18

1 u = 18 ÷ 3 = 6

Number of cookies that Jenson had at first
= 7 u
= 7 x 6
= 42 

(b)
Total number of cookies that the 3 of them bought
= 7 u + 10 u + 5 u + 5
= 22 u + 5
= 22 x 6 + 5
= 132 + 5
= 137

Answer(s): (a) 42; (b) 137