Vaidev, Brandon and Ken bought some biscuits. After Vaidev ate ²₅ of his biscuits, Brandon ate ³₄ of his biscuits and Ken ate 7 biscuits, each of them had the same number of biscuits left. Vaidev had 28 less biscuits than Brandon at first.

1. How many biscuits did Vaidev have at first?
2. How many biscuits did the 3 of them buy altogether? 

	Vaidev	Brandon	Ken
Before	5 u	4x3 = 12 u	3 u + 7
Change	- 2 u	- 3x3 = - 9 u	- 7
After	3 u	1x3 = 3 u	3 u

(a)
The number of biscuits that Vaidev and Brandon each had in the end is the same. Make the number of biscuits that Vaidev and Brandon each had in the end the same.  LCM of 3 and 1 is 3.

Number of biscuits that Vaidev had less than Brandon at first
= 12 u - 5 u
= 7 u

7 u = 28

1 u = 28 ÷ 7 = 4

Number of biscuits that Vaidev had at first
= 5 u
= 5 x 4
= 20 

(b)
Total number of biscuits that the 3 of them bought
= 5 u + 12 u + 3 u + 7
= 20 u + 7
= 20 x 4 + 7
= 80 + 7
= 87

Answer(s): (a) 20; (b) 87