Oscar, Peter and Simon bought some biscuits. After Oscar ate ³₈ of his biscuits, Peter ate ²₃ of his biscuits and Simon ate 10 biscuits, each of them had the same number of biscuits left. Oscar had 49 less biscuits than Peter at first.

1. How many biscuits did Oscar have at first?
2. How many biscuits did the 3 of them buy altogether? 

	Oscar	Peter	Simon
Before	8 u	3x5 = 15 u	5 u + 10
Change	- 3 u	- 2x5 = - 10 u	- 10
After	5 u	1x5 = 5 u	5 u

(a)
The number of biscuits that Oscar and Peter each had in the end is the same. Make the number of biscuits that Oscar and Peter each had in the end the same.  LCM of 5 and 1 is 5.

Number of biscuits that Oscar had less than Peter at first
= 15 u - 8 u
= 7 u

7 u = 49

1 u = 49 ÷ 7 = 7

Number of biscuits that Oscar had at first
= 8 u
= 8 x 7
= 56 

(b)
Total number of biscuits that the 3 of them bought
= 8 u + 15 u + 5 u + 10
= 28 u + 10
= 28 x 7 + 10
= 196 + 10
= 206

Answer(s): (a) 56; (b) 206