Henry, Seth and Bryan bought some muffins. After Henry ate ⁴₇ of his muffins, Seth ate ⁴₅ of his muffins and Bryan ate 2 muffins, each of them had the same number of muffins left. Henry had 40 less muffins than Seth at first.

1. How many muffins did Henry have at first?
2. How many muffins did the 3 of them buy altogether? 

	Henry	Seth	Bryan
Before	7 u	5x3 = 15 u	3 u + 2
Change	- 4 u	- 4x3 = - 12 u	- 2
After	3 u	1x3 = 3 u	3 u

(a)
The number of muffins that Henry and Seth each had in the end is the same. Make the number of muffins that Henry and Seth each had in the end the same.  LCM of 3 and 1 is 3.

Number of muffins that Henry had less than Seth at first
= 15 u - 7 u
= 8 u

8 u = 40

1 u = 40 ÷ 8 = 5

Number of muffins that Henry had at first
= 7 u
= 7 x 5
= 35 

(b)
Total number of muffins that the 3 of them bought
= 7 u + 15 u + 3 u + 2
= 25 u + 2
= 25 x 5 + 2
= 125 + 2
= 127

Answer(s): (a) 35; (b) 127