Glen and Liam had 67 shortbreads altogether. After Glen ate
15 of his shortbreads and Liam ate 4 shortbreads, the number of shortbreads Liam had left was four times the number of shortbreads Glen had left. How many more shortbreads did Liam have than Glen at first?
|
Glen |
Liam |
Total |
Before |
5 u |
16 u + 4 |
67 |
Change |
- 1 u |
- 4 |
|
After |
4 u |
|
|
Comparing Glen and Liam in the end |
1x4 = 4 u |
4x4 = 16 u |
|
The number of shortbreads that Glen had in the end is the same. Make the number of shortbreads that Glen had in the end the same. LCM of 4 and 1 is 4.
Total number of shortbreads at first
= 5 u + 16 u + 4
= 21 u + 4
21 u + 4 = 67
21 u = 67 - 4
21 u = 63
1 u = 63 ÷ 21 = 3
Number of shortbreads that Glen had at first
= 5 u
= 5 x 3
= 15
Number of shortbreads that Liam had at first
= 67 - 15
= 52
Number of shortbreads that Liam had more than Glen at first
= 52 - 15
= 37
Answer(s): 37