Glen and Lee had 71 scones altogether. After Glen ate
16 of his scones and Lee ate 8 scones, the number of scones Lee had left was thrice the number of scones Glen had left. How many more scones did Lee have than Glen at first?
| |
Glen |
Lee |
Total |
| Before |
6 u |
15 u + 8 |
71 |
| Change |
- 1 u |
- 8 |
|
| After |
5 u |
|
|
Comparing Glen and
Lee in the end |
1x5 =
5 u |
3x5 =
15 u |
|
The number of scones that Glen had in the end is the same. Make the number of scones that Glen had in the end the same. LCM of 5 and 1 is 5.
Total number of scones at first
= 6 u + 15 u + 8
= 21 u + 8
21 u + 8 = 71
21 u = 71 - 8
21 u = 63
1 u = 63 ÷ 21 = 3
Number of scones that Glen had at first
= 6 u
= 6 x 3
= 18
Number of scones that Lee had at first
= 71 - 18
= 53
Number of scones that Lee had more than Glen at first
= 53 - 18
= 35
Answer(s): 35
