Warren and Zane had 93 croissants altogether. After Warren ate
15 of his croissants and Zane ate 8 croissants, the number of croissants Zane had left was thrice the number of croissants Warren had left. How many more croissants did Zane have than Warren at first?
|
Warren |
Zane |
Total |
Before |
5 u |
12 u + 8 |
93 |
Change |
- 1 u |
- 8 |
|
After |
4 u |
|
|
Comparing Warren and Zane in the end |
1x4 = 4 u |
3x4 = 12 u |
|
The number of croissants that Warren had in the end is the same. Make the number of croissants that Warren had in the end the same. LCM of 4 and 1 is 4.
Total number of croissants at first
= 5 u + 12 u + 8
= 17 u + 8
17 u + 8 = 93
17 u = 93 - 8
17 u = 85
1 u = 85 ÷ 17 = 5
Number of croissants that Warren had at first
= 5 u
= 5 x 5
= 25
Number of croissants that Zane had at first
= 93 - 25
= 68
Number of croissants that Zane had more than Warren at first
= 68 - 25
= 43
Answer(s): 43