Charlie and Jeremy had 57 cookies altogether. After Charlie ate ¹₃ of his cookies and Jeremy ate 8 cookies, the number of cookies Jeremy had left was twice the number of cookies Charlie had left. How many more cookies did Jeremy have than Charlie at first?

	Charlie	Jeremy	Total
Before	3 u	4 u + 8	57
Change	- 1 u	- 8
After	2 u
Comparing Charlie and Jeremy in the end	1x2 = 2 u	2x2 = 4 u

The number of cookies that Charlie had in the end is the same. Make the number of cookies that Charlie had in the end the same.  LCM of 2 and 1 is 2.

Total number of cookies at first
= 3 u + 4 u + 8
= 7 u + 8

7 u + 8 = 57
7 u = 57 - 8
7 u = 49 

1 u = 49 ÷ 7 = 7

Number of cookies that Charlie had at first
= 3 u
= 3 x 7
= 21

Number of cookies that Jeremy had at first
= 57 - 21
= 36

Number of cookies that Jeremy had more than Charlie at first
= 36 - 21
= 15

Answer(s): 15