Daniel and Cody had 27 cookies altogether. After Daniel ate
13 of his cookies and Cody ate 9 cookies, the number of cookies Cody had left was thrice the number of cookies Daniel had left. How many more cookies did Cody have than Daniel at first?
|
Daniel |
Cody |
Total |
Before |
3 u |
6 u + 9 |
27 |
Change |
- 1 u |
- 9 |
|
After |
2 u |
|
|
Comparing Daniel and Cody in the end |
1x2 = 2 u |
3x2 = 6 u |
|
The number of cookies that Daniel had in the end is the same. Make the number of cookies that Daniel had in the end the same. LCM of 2 and 1 is 2.
Total number of cookies at first
= 3 u + 6 u + 9
= 9 u + 9
9 u + 9 = 27
9 u = 27 - 9
9 u = 18
1 u = 18 ÷ 9 = 2
Number of cookies that Daniel had at first
= 3 u
= 3 x 2
= 6
Number of cookies that Cody had at first
= 27 - 6
= 21
Number of cookies that Cody had more than Daniel at first
= 21 - 6
= 15
Answer(s): 15