Justin and Xavier had 46 cookies altogether. After Justin ate ¹₃ of his cookies and Xavier ate 4 cookies, the number of cookies Xavier had left was twice the number of cookies Justin had left. How many more cookies did Xavier have than Justin at first?

	Justin	Xavier	Total
Before	3 u	4 u + 4	46
Change	- 1 u	- 4
After	2 u
Comparing Justin and Xavier in the end	1x2 = 2 u	2x2 = 4 u

The number of cookies that Justin had in the end is the same. Make the number of cookies that Justin had in the end the same.  LCM of 2 and 1 is 2.

Total number of cookies at first
= 3 u + 4 u + 4
= 7 u + 4

7 u + 4 = 46
7 u = 46 - 4
7 u = 42 

1 u = 42 ÷ 7 = 6

Number of cookies that Justin had at first
= 3 u
= 3 x 6
= 18

Number of cookies that Xavier had at first
= 46 - 18
= 28

Number of cookies that Xavier had more than Justin at first
= 28 - 18
= 10

Answer(s): 10