Justin and Tommy had 83 biscuits altogether. After Justin ate
14 of his biscuits and Tommy ate 3 biscuits, the number of biscuits Tommy had left was twice the number of biscuits Justin had left. How many more biscuits did Tommy have than Justin at first?
|
Justin |
Tommy |
Total |
Before |
4 u |
6 u + 3 |
83 |
Change |
- 1 u |
- 3 |
|
After |
3 u |
|
|
Comparing Justin and Tommy in the end |
1x3 = 3 u |
2x3 = 6 u |
|
The number of biscuits that Justin had in the end is the same. Make the number of biscuits that Justin had in the end the same. LCM of 3 and 1 is 3.
Total number of biscuits at first
= 4 u + 6 u + 3
= 10 u + 3
10 u + 3 = 83
10 u = 83 - 3
10 u = 80
1 u = 80 ÷ 10 = 8
Number of biscuits that Justin had at first
= 4 u
= 4 x 8
= 32
Number of biscuits that Tommy had at first
= 83 - 32
= 51
Number of biscuits that Tommy had more than Justin at first
= 51 - 32
= 19
Answer(s): 19