Caden and Cole had 73 macarons altogether. After Caden ate
13 of his macarons and Cole ate 7 macarons, the number of macarons Cole had left was four times the number of macarons Caden had left. How many more macarons did Cole have than Caden at first?
|
Caden |
Cole |
Total |
Before |
3 u |
8 u + 7 |
73 |
Change |
- 1 u |
- 7 |
|
After |
2 u |
|
|
Comparing Caden and Cole in the end |
1x2 = 2 u |
4x2 = 8 u |
|
The number of macarons that Caden had in the end is the same. Make the number of macarons that Caden had in the end the same. LCM of 2 and 1 is 2.
Total number of macarons at first
= 3 u + 8 u + 7
= 11 u + 7
11 u + 7 = 73
11 u = 73 - 7
11 u = 66
1 u = 66 ÷ 11 = 6
Number of macarons that Caden had at first
= 3 u
= 3 x 6
= 18
Number of macarons that Cole had at first
= 73 - 18
= 55
Number of macarons that Cole had more than Caden at first
= 55 - 18
= 37
Answer(s): 37