Jeremy and Archie had 86 tarts altogether. After Jeremy ate
15 of his tarts and Archie ate 2 tarts, the number of tarts Archie had left was four times the number of tarts Jeremy had left. How many more tarts did Archie have than Jeremy at first?
|
Jeremy |
Archie |
Total |
Before |
5 u |
16 u + 2 |
86 |
Change |
- 1 u |
- 2 |
|
After |
4 u |
|
|
Comparing Jeremy and Archie in the end |
1x4 = 4 u |
4x4 = 16 u |
|
The number of tarts that Jeremy had in the end is the same. Make the number of tarts that Jeremy had in the end the same. LCM of 4 and 1 is 4.
Total number of tarts at first
= 5 u + 16 u + 2
= 21 u + 2
21 u + 2 = 86
21 u = 86 - 2
21 u = 84
1 u = 84 ÷ 21 = 4
Number of tarts that Jeremy had at first
= 5 u
= 5 x 4
= 20
Number of tarts that Archie had at first
= 86 - 20
= 66
Number of tarts that Archie had more than Jeremy at first
= 66 - 20
= 46
Answer(s): 46