Oscar and Ian had 55 croissants altogether. After Oscar ate ¹₃ of his croissants and Ian ate 3 croissants, the number of croissants Ian had left was five times the number of croissants Oscar had left. How many more croissants did Ian have than Oscar at first?

	Oscar	Ian	Total
Before	3 u	10 u + 3	55
Change	- 1 u	- 3
After	2 u
Comparing Oscar and Ian in the end	1x2 = 2 u	5x2 = 10 u

The number of croissants that Oscar had in the end is the same. Make the number of croissants that Oscar had in the end the same.  LCM of 2 and 1 is 2.

Total number of croissants at first
= 3 u + 10 u + 3
= 13 u + 3

13 u + 3 = 55
13 u = 55 - 3
13 u = 52 

1 u = 52 ÷ 13 = 4

Number of croissants that Oscar had at first
= 3 u
= 3 x 4
= 12

Number of croissants that Ian had at first
= 55 - 12
= 43

Number of croissants that Ian had more than Oscar at first
= 43 - 12
= 31

Answer(s): 31