Zane and Bobby had 57 macarons altogether. After Zane ate ¹₃ of his macarons and Bobby ate 8 macarons, the number of macarons Bobby had left was twice the number of macarons Zane had left. How many more macarons did Bobby have than Zane at first?

	Zane	Bobby	Total
Before	3 u	4 u + 8	57
Change	- 1 u	- 8
After	2 u
Comparing Zane and Bobby in the end	1x2 = 2 u	2x2 = 4 u

The number of macarons that Zane had in the end is the same. Make the number of macarons that Zane had in the end the same.  LCM of 2 and 1 is 2.

Total number of macarons at first
= 3 u + 4 u + 8
= 7 u + 8

7 u + 8 = 57
7 u = 57 - 8
7 u = 49 

1 u = 49 ÷ 7 = 7

Number of macarons that Zane had at first
= 3 u
= 3 x 7
= 21

Number of macarons that Bobby had at first
= 57 - 21
= 36

Number of macarons that Bobby had more than Zane at first
= 36 - 21
= 15

Answer(s): 15