Oscar and Seth had 98 macarons altogether. After Oscar ate
13 of his macarons and Seth ate 7 macarons, the number of macarons Seth had left was five times the number of macarons Oscar had left. How many more macarons did Seth have than Oscar at first?
|
Oscar |
Seth |
Total |
Before |
3 u |
10 u + 7 |
98 |
Change |
- 1 u |
- 7 |
|
After |
2 u |
|
|
Comparing Oscar and Seth in the end |
1x2 = 2 u |
5x2 = 10 u |
|
The number of macarons that Oscar had in the end is the same. Make the number of macarons that Oscar had in the end the same. LCM of 2 and 1 is 2.
Total number of macarons at first
= 3 u + 10 u + 7
= 13 u + 7
13 u + 7 = 98
13 u = 98 - 7
13 u = 91
1 u = 91 ÷ 13 = 7
Number of macarons that Oscar had at first
= 3 u
= 3 x 7
= 21
Number of macarons that Seth had at first
= 98 - 21
= 77
Number of macarons that Seth had more than Oscar at first
= 77 - 21
= 56
Answer(s): 56