Vaidev and Pierre had 68 cookies altogether. After Vaidev ate ¹₄ of his cookies and Pierre ate 8 cookies, the number of cookies Pierre had left was twice the number of cookies Vaidev had left. How many more cookies did Pierre have than Vaidev at first?

	Vaidev	Pierre	Total
Before	4 u	6 u + 8	68
Change	- 1 u	- 8
After	3 u
Comparing Vaidev and Pierre in the end	1x3 = 3 u	2x3 = 6 u

The number of cookies that Vaidev had in the end is the same. Make the number of cookies that Vaidev had in the end the same.  LCM of 3 and 1 is 3.

Total number of cookies at first
= 4 u + 6 u + 8
= 10 u + 8

10 u + 8 = 68
10 u = 68 - 8
10 u = 60 

1 u = 60 ÷ 10 = 6

Number of cookies that Vaidev had at first
= 4 u
= 4 x 6
= 24

Number of cookies that Pierre had at first
= 68 - 24
= 44

Number of cookies that Pierre had more than Vaidev at first
= 44 - 24
= 20

Answer(s): 20