Billy and Howard had 100 wafers altogether. After Billy ate ¹₄ of his wafers and Howard ate 10 wafers, the number of wafers Howard had left was twice the number of wafers Billy had left. How many more wafers did Howard have than Billy at first?

	Billy	Howard	Total
Before	4 u	6 u + 10	100
Change	- 1 u	- 10
After	3 u
Comparing Billy and Howard in the end	1x3 = 3 u	2x3 = 6 u

The number of wafers that Billy had in the end is the same. Make the number of wafers that Billy had in the end the same.  LCM of 3 and 1 is 3.

Total number of wafers at first
= 4 u + 6 u + 10
= 10 u + 10

10 u + 10 = 100
10 u = 100 - 10
10 u = 90 

1 u = 90 ÷ 10 = 9

Number of wafers that Billy had at first
= 4 u
= 4 x 9
= 36

Number of wafers that Howard had at first
= 100 - 36
= 64

Number of wafers that Howard had more than Billy at first
= 64 - 36
= 28

Answer(s): 28