Albert and Cole had 69 tarts altogether. After Albert ate ¹₄ of his tarts and Cole ate 5 tarts, the number of tarts Cole had left was four times the number of tarts Albert had left. How many more tarts did Cole have than Albert at first?

	Albert	Cole	Total
Before	4 u	12 u + 5	69
Change	- 1 u	- 5
After	3 u
Comparing Albert and Cole in the end	1x3 = 3 u	4x3 = 12 u

The number of tarts that Albert had in the end is the same. Make the number of tarts that Albert had in the end the same.  LCM of 3 and 1 is 3.

Total number of tarts at first
= 4 u + 12 u + 5
= 16 u + 5

16 u + 5 = 69
16 u = 69 - 5
16 u = 64 

1 u = 64 ÷ 16 = 4

Number of tarts that Albert had at first
= 4 u
= 4 x 4
= 16

Number of tarts that Cole had at first
= 69 - 16
= 53

Number of tarts that Cole had more than Albert at first
= 53 - 16
= 37

Answer(s): 37