Nick and Owen had 42 biscuits altogether. After Nick ate
16 of his biscuits and Owen ate 10 biscuits, the number of biscuits Owen had left was twice the number of biscuits Nick had left. How many more biscuits did Owen have than Nick at first?
|
Nick |
Owen |
Total |
Before |
6 u |
10 u + 10 |
42 |
Change |
- 1 u |
- 10 |
|
After |
5 u |
|
|
Comparing Nick and Owen in the end |
1x5 = 5 u |
2x5 = 10 u |
|
The number of biscuits that Nick had in the end is the same. Make the number of biscuits that Nick had in the end the same. LCM of 5 and 1 is 5.
Total number of biscuits at first
= 6 u + 10 u + 10
= 16 u + 10
16 u + 10 = 42
16 u = 42 - 10
16 u = 32
1 u = 32 ÷ 16 = 2
Number of biscuits that Nick had at first
= 6 u
= 6 x 2
= 12
Number of biscuits that Owen had at first
= 42 - 12
= 30
Number of biscuits that Owen had more than Nick at first
= 30 - 12
= 18
Answer(s): 18