Charlie and Liam had 85 cookies altogether. After Charlie ate ¹₄ of his cookies and Liam ate 5 cookies, the number of cookies Liam had left was twice the number of cookies Charlie had left. How many more cookies did Liam have than Charlie at first?

	Charlie	Liam	Total
Before	4 u	6 u + 5	85
Change	- 1 u	- 5
After	3 u
Comparing Charlie and Liam in the end	1x3 = 3 u	2x3 = 6 u

The number of cookies that Charlie had in the end is the same. Make the number of cookies that Charlie had in the end the same.  LCM of 3 and 1 is 3.

Total number of cookies at first
= 4 u + 6 u + 5
= 10 u + 5

10 u + 5 = 85
10 u = 85 - 5
10 u = 80 

1 u = 80 ÷ 10 = 8

Number of cookies that Charlie had at first
= 4 u
= 4 x 8
= 32

Number of cookies that Liam had at first
= 85 - 32
= 53

Number of cookies that Liam had more than Charlie at first
= 53 - 32
= 21

Answer(s): 21