Wesley and Eric had 90 biscuits altogether. After Wesley ate ¹₃ of his biscuits and Eric ate 2 biscuits, the number of biscuits Eric had left was four times the number of biscuits Wesley had left. How many more biscuits did Eric have than Wesley at first?

	Wesley	Eric	Total
Before	3 u	8 u + 2	90
Change	- 1 u	- 2
After	2 u
Comparing Wesley and Eric in the end	1x2 = 2 u	4x2 = 8 u

The number of biscuits that Wesley had in the end is the same. Make the number of biscuits that Wesley had in the end the same.  LCM of 2 and 1 is 2.

Total number of biscuits at first
= 3 u + 8 u + 2
= 11 u + 2

11 u + 2 = 90
11 u = 90 - 2
11 u = 88 

1 u = 88 ÷ 11 = 8

Number of biscuits that Wesley had at first
= 3 u
= 3 x 8
= 24

Number of biscuits that Eric had at first
= 90 - 24
= 66

Number of biscuits that Eric had more than Wesley at first
= 66 - 24
= 42

Answer(s): 42