Daniel and Jeremy had 80 croissants altogether. After Daniel ate ¹₆ of his croissants and Jeremy ate 2 croissants, the number of croissants Jeremy had left was four times the number of croissants Daniel had left. How many more croissants did Jeremy have than Daniel at first?

	Daniel	Jeremy	Total
Before	6 u	20 u + 2	80
Change	- 1 u	- 2
After	5 u
Comparing Daniel and Jeremy in the end	1x5 = 5 u	4x5 = 20 u

The number of croissants that Daniel had in the end is the same. Make the number of croissants that Daniel had in the end the same.  LCM of 5 and 1 is 5.

Total number of croissants at first
= 6 u + 20 u + 2
= 26 u + 2

26 u + 2 = 80
26 u = 80 - 2
26 u = 78 

1 u = 78 ÷ 26 = 3

Number of croissants that Daniel had at first
= 6 u
= 6 x 3
= 18

Number of croissants that Jeremy had at first
= 80 - 18
= 62

Number of croissants that Jeremy had more than Daniel at first
= 62 - 18
= 44

Answer(s): 44