Oscar and Carl had 43 croissants altogether. After Oscar ate ¹₄ of his croissants and Carl ate 3 croissants, the number of croissants Carl had left was twice the number of croissants Oscar had left. How many more croissants did Carl have than Oscar at first?

	Oscar	Carl	Total
Before	4 u	6 u + 3	43
Change	- 1 u	- 3
After	3 u
Comparing Oscar and Carl in the end	1x3 = 3 u	2x3 = 6 u

The number of croissants that Oscar had in the end is the same. Make the number of croissants that Oscar had in the end the same.  LCM of 3 and 1 is 3.

Total number of croissants at first
= 4 u + 6 u + 3
= 10 u + 3

10 u + 3 = 43
10 u = 43 - 3
10 u = 40 

1 u = 40 ÷ 10 = 4

Number of croissants that Oscar had at first
= 4 u
= 4 x 4
= 16

Number of croissants that Carl had at first
= 43 - 16
= 27

Number of croissants that Carl had more than Oscar at first
= 27 - 16
= 11

Answer(s): 11