Rael and Carl had 35 croissants altogether. After Rael ate ¹₃ of his croissants and Carl ate 7 croissants, the number of croissants Carl had left was twice the number of croissants Rael had left. How many more croissants did Carl have than Rael at first?

	Rael	Carl	Total
Before	3 u	4 u + 7	35
Change	- 1 u	- 7
After	2 u
Comparing Rael and Carl in the end	1x2 = 2 u	2x2 = 4 u

The number of croissants that Rael had in the end is the same. Make the number of croissants that Rael had in the end the same.  LCM of 2 and 1 is 2.

Total number of croissants at first
= 3 u + 4 u + 7
= 7 u + 7

7 u + 7 = 35
7 u = 35 - 7
7 u = 28 

1 u = 28 ÷ 7 = 4

Number of croissants that Rael had at first
= 3 u
= 3 x 4
= 12

Number of croissants that Carl had at first
= 35 - 12
= 23

Number of croissants that Carl had more than Rael at first
= 23 - 12
= 11

Answer(s): 11