Ethan and Andy had 85 tarts altogether. After Ethan ate
16 of his tarts and Andy ate 7 tarts, the number of tarts Andy had left was four times the number of tarts Ethan had left. How many more tarts did Andy have than Ethan at first?
|
Ethan |
Andy |
Total |
Before |
6 u |
20 u + 7 |
85 |
Change |
- 1 u |
- 7 |
|
After |
5 u |
|
|
Comparing Ethan and Andy in the end |
1x5 = 5 u |
4x5 = 20 u |
|
The number of tarts that Ethan had in the end is the same. Make the number of tarts that Ethan had in the end the same. LCM of 5 and 1 is 5.
Total number of tarts at first
= 6 u + 20 u + 7
= 26 u + 7
26 u + 7 = 85
26 u = 85 - 7
26 u = 78
1 u = 78 ÷ 26 = 3
Number of tarts that Ethan had at first
= 6 u
= 6 x 3
= 18
Number of tarts that Andy had at first
= 85 - 18
= 67
Number of tarts that Andy had more than Ethan at first
= 67 - 18
= 49
Answer(s): 49