Fabian and Zane had 48 croissants altogether. After Fabian ate ¹₄ of his croissants and Zane ate 8 croissants, the number of croissants Zane had left was twice the number of croissants Fabian had left. How many more croissants did Zane have than Fabian at first?

	Fabian	Zane	Total
Before	4 u	6 u + 8	48
Change	- 1 u	- 8
After	3 u
Comparing Fabian and Zane in the end	1x3 = 3 u	2x3 = 6 u

The number of croissants that Fabian had in the end is the same. Make the number of croissants that Fabian had in the end the same.  LCM of 3 and 1 is 3.

Total number of croissants at first
= 4 u + 6 u + 8
= 10 u + 8

10 u + 8 = 48
10 u = 48 - 8
10 u = 40 

1 u = 40 ÷ 10 = 4

Number of croissants that Fabian had at first
= 4 u
= 4 x 4
= 16

Number of croissants that Zane had at first
= 48 - 16
= 32

Number of croissants that Zane had more than Fabian at first
= 32 - 16
= 16

Answer(s): 16