Sam and Will had 26 wafers altogether. After Sam ate
14 of his wafers and Will ate 6 wafers, the number of wafers Will had left was twice the number of wafers Sam had left. How many more wafers did Will have than Sam at first?
| |
Sam |
Will |
Total |
| Before |
4 u |
6 u + 6 |
26 |
| Change |
- 1 u |
- 6 |
|
| After |
3 u |
|
|
Comparing Sam and
Will in the end |
1x3 =
3 u |
2x3 =
6 u |
|
The number of wafers that Sam had in the end is the same. Make the number of wafers that Sam had in the end the same. LCM of 3 and 1 is 3.
Total number of wafers at first
= 4 u + 6 u + 6
= 10 u + 6
10 u + 6 = 26
10 u = 26 - 6
10 u = 20
1 u = 20 ÷ 10 = 2
Number of wafers that Sam had at first
= 4 u
= 4 x 2
= 8
Number of wafers that Will had at first
= 26 - 8
= 18
Number of wafers that Will had more than Sam at first
= 18 - 8
= 10
Answer(s): 10
