Eric and Caden had 46 wafers altogether. After Eric ate ¹₃ of his wafers and Caden ate 7 wafers, the number of wafers Caden had left was five times the number of wafers Eric had left. How many more wafers did Caden have than Eric at first?

	Eric	Caden	Total
Before	3 u	10 u + 7	46
Change	- 1 u	- 7
After	2 u
Comparing Eric and Caden in the end	1x2 = 2 u	5x2 = 10 u

The number of wafers that Eric had in the end is the same. Make the number of wafers that Eric had in the end the same.  LCM of 2 and 1 is 2.

Total number of wafers at first
= 3 u + 10 u + 7
= 13 u + 7

13 u + 7 = 46
13 u = 46 - 7
13 u = 39 

1 u = 39 ÷ 13 = 3

Number of wafers that Eric had at first
= 3 u
= 3 x 3
= 9

Number of wafers that Caden had at first
= 46 - 9
= 37

Number of wafers that Caden had more than Eric at first
= 37 - 9
= 28

Answer(s): 28