Neave and Luke had 69 macarons altogether. After Neave ate
14 of his macarons and Luke ate 9 macarons, the number of macarons Luke had left was twice the number of macarons Neave had left. How many more macarons did Luke have than Neave at first?
|
Neave |
Luke |
Total |
Before |
4 u |
6 u + 9 |
69 |
Change |
- 1 u |
- 9 |
|
After |
3 u |
|
|
Comparing Neave and Luke in the end |
1x3 = 3 u |
2x3 = 6 u |
|
The number of macarons that Neave had in the end is the same. Make the number of macarons that Neave had in the end the same. LCM of 3 and 1 is 3.
Total number of macarons at first
= 4 u + 6 u + 9
= 10 u + 9
10 u + 9 = 69
10 u = 69 - 9
10 u = 60
1 u = 60 ÷ 10 = 6
Number of macarons that Neave had at first
= 4 u
= 4 x 6
= 24
Number of macarons that Luke had at first
= 69 - 24
= 45
Number of macarons that Luke had more than Neave at first
= 45 - 24
= 21
Answer(s): 21