Archie and Valen had 73 wafers altogether. After Archie ate
14 of his wafers and Valen ate 3 wafers, the number of wafers Valen had left was twice the number of wafers Archie had left. How many more wafers did Valen have than Archie at first?
|
Archie |
Valen |
Total |
Before |
4 u |
6 u + 3 |
73 |
Change |
- 1 u |
- 3 |
|
After |
3 u |
|
|
Comparing Archie and Valen in the end |
1x3 = 3 u |
2x3 = 6 u |
|
The number of wafers that Archie had in the end is the same. Make the number of wafers that Archie had in the end the same. LCM of 3 and 1 is 3.
Total number of wafers at first
= 4 u + 6 u + 3
= 10 u + 3
10 u + 3 = 73
10 u = 73 - 3
10 u = 70
1 u = 70 ÷ 10 = 7
Number of wafers that Archie had at first
= 4 u
= 4 x 7
= 28
Number of wafers that Valen had at first
= 73 - 28
= 45
Number of wafers that Valen had more than Archie at first
= 45 - 28
= 17
Answer(s): 17