Dylan and Charlie had 86 tarts altogether. After Dylan ate ¹₄ of his tarts and Charlie ate 8 tarts, the number of tarts Charlie had left was thrice the number of tarts Dylan had left. How many more tarts did Charlie have than Dylan at first?

	Dylan	Charlie	Total
Before	4 u	9 u + 8	86
Change	- 1 u	- 8
After	3 u
Comparing Dylan and Charlie in the end	1x3 = 3 u	3x3 = 9 u

The number of tarts that Dylan had in the end is the same. Make the number of tarts that Dylan had in the end the same.  LCM of 3 and 1 is 3.

Total number of tarts at first
= 4 u + 9 u + 8
= 13 u + 8

13 u + 8 = 86
13 u = 86 - 8
13 u = 78 

1 u = 78 ÷ 13 = 6

Number of tarts that Dylan had at first
= 4 u
= 4 x 6
= 24

Number of tarts that Charlie had at first
= 86 - 24
= 62

Number of tarts that Charlie had more than Dylan at first
= 62 - 24
= 38

Answer(s): 38