Liam and Jeremy had 92 tarts altogether. After Liam ate
13 of his tarts and Jeremy ate 4 tarts, the number of tarts Jeremy had left was four times the number of tarts Liam had left. How many more tarts did Jeremy have than Liam at first?
|
Liam |
Jeremy |
Total |
Before |
3 u |
8 u + 4 |
92 |
Change |
- 1 u |
- 4 |
|
After |
2 u |
|
|
Comparing Liam and Jeremy in the end |
1x2 = 2 u |
4x2 = 8 u |
|
The number of tarts that Liam had in the end is the same. Make the number of tarts that Liam had in the end the same. LCM of 2 and 1 is 2.
Total number of tarts at first
= 3 u + 8 u + 4
= 11 u + 4
11 u + 4 = 92
11 u = 92 - 4
11 u = 88
1 u = 88 ÷ 11 = 8
Number of tarts that Liam had at first
= 3 u
= 3 x 8
= 24
Number of tarts that Jeremy had at first
= 92 - 24
= 68
Number of tarts that Jeremy had more than Liam at first
= 68 - 24
= 44
Answer(s): 44