Luis and Carl had 100 croissants altogether. After Luis ate ¹₆ of his croissants and Carl ate 7 croissants, the number of croissants Carl had left was five times the number of croissants Luis had left. How many more croissants did Carl have than Luis at first?

	Luis	Carl	Total
Before	6 u	25 u + 7	100
Change	- 1 u	- 7
After	5 u
Comparing Luis and Carl in the end	1x5 = 5 u	5x5 = 25 u

The number of croissants that Luis had in the end is the same. Make the number of croissants that Luis had in the end the same.  LCM of 5 and 1 is 5.

Total number of croissants at first
= 6 u + 25 u + 7
= 31 u + 7

31 u + 7 = 100
31 u = 100 - 7
31 u = 93 

1 u = 93 ÷ 31 = 3

Number of croissants that Luis had at first
= 6 u
= 6 x 3
= 18

Number of croissants that Carl had at first
= 100 - 18
= 82

Number of croissants that Carl had more than Luis at first
= 82 - 18
= 64

Answer(s): 64