Sean and Jeremy had 33 muffins altogether. After Sean ate
14 of his muffins and Jeremy ate 7 muffins, the number of muffins Jeremy had left was thrice the number of muffins Sean had left. How many more muffins did Jeremy have than Sean at first?
|
Sean |
Jeremy |
Total |
Before |
4 u |
9 u + 7 |
33 |
Change |
- 1 u |
- 7 |
|
After |
3 u |
|
|
Comparing Sean and Jeremy in the end |
1x3 = 3 u |
3x3 = 9 u |
|
The number of muffins that Sean had in the end is the same. Make the number of muffins that Sean had in the end the same. LCM of 3 and 1 is 3.
Total number of muffins at first
= 4 u + 9 u + 7
= 13 u + 7
13 u + 7 = 33
13 u = 33 - 7
13 u = 26
1 u = 26 ÷ 13 = 2
Number of muffins that Sean had at first
= 4 u
= 4 x 2
= 8
Number of muffins that Jeremy had at first
= 33 - 8
= 25
Number of muffins that Jeremy had more than Sean at first
= 25 - 8
= 17
Answer(s): 17