Paul and Vincent had 81 wafers altogether. After Paul ate ¹₄ of his wafers and Vincent ate 5 wafers, the number of wafers Vincent had left was five times the number of wafers Paul had left. How many more wafers did Vincent have than Paul at first?

	Paul	Vincent	Total
Before	4 u	15 u + 5	81
Change	- 1 u	- 5
After	3 u
Comparing Paul and Vincent in the end	1x3 = 3 u	5x3 = 15 u

The number of wafers that Paul had in the end is the same. Make the number of wafers that Paul had in the end the same.  LCM of 3 and 1 is 3.

Total number of wafers at first
= 4 u + 15 u + 5
= 19 u + 5

19 u + 5 = 81
19 u = 81 - 5
19 u = 76 

1 u = 76 ÷ 19 = 4

Number of wafers that Paul had at first
= 4 u
= 4 x 4
= 16

Number of wafers that Vincent had at first
= 81 - 16
= 65

Number of wafers that Vincent had more than Paul at first
= 65 - 16
= 49

Answer(s): 49