Warren and Caden had 81 shortbreads altogether. After Warren ate ¹₄ of his shortbreads and Caden ate 5 shortbreads, the number of shortbreads Caden had left was five times the number of shortbreads Warren had left. How many more shortbreads did Caden have than Warren at first?

	Warren	Caden	Total
Before	4 u	15 u + 5	81
Change	- 1 u	- 5
After	3 u
Comparing Warren and Caden in the end	1x3 = 3 u	5x3 = 15 u

The number of shortbreads that Warren had in the end is the same. Make the number of shortbreads that Warren had in the end the same.  LCM of 3 and 1 is 3.

Total number of shortbreads at first
= 4 u + 15 u + 5
= 19 u + 5

19 u + 5 = 81
19 u = 81 - 5
19 u = 76 

1 u = 76 ÷ 19 = 4

Number of shortbreads that Warren had at first
= 4 u
= 4 x 4
= 16

Number of shortbreads that Caden had at first
= 81 - 16
= 65

Number of shortbreads that Caden had more than Warren at first
= 65 - 16
= 49

Answer(s): 49