Xavier and Lee had 38 puffs altogether. After Xavier ate
14 of his puffs and Lee ate 8 puffs, the number of puffs Lee had left was twice the number of puffs Xavier had left. How many more puffs did Lee have than Xavier at first?
| |
Xavier |
Lee |
Total |
| Before |
4 u |
6 u + 8 |
38 |
| Change |
- 1 u |
- 8 |
|
| After |
3 u |
|
|
Comparing Xavier and
Lee in the end |
1x3 =
3 u |
2x3 =
6 u |
|
The number of puffs that Xavier had in the end is the same. Make the number of puffs that Xavier had in the end the same. LCM of 3 and 1 is 3.
Total number of puffs at first
= 4 u + 6 u + 8
= 10 u + 8
10 u + 8 = 38
10 u = 38 - 8
10 u = 30
1 u = 30 ÷ 10 = 3
Number of puffs that Xavier had at first
= 4 u
= 4 x 3
= 12
Number of puffs that Lee had at first
= 38 - 12
= 26
Number of puffs that Lee had more than Xavier at first
= 26 - 12
= 14
Answer(s): 14
